6(x+1)=4[x-(3-x)]

Solution for 6(x+1)=4[x-(3-x)] equation:

Simplifying
6(x + 1) = 4[x + -1(3 + -1x)]

Reorder the terms:
6(1 + x) = 4[x + -1(3 + -1x)]
(1 * 6 + x * 6) = 4[x + -1(3 + -1x)]
(6 + 6x) = 4[x + -1(3 + -1x)]
6 + 6x = 4[x + (3 * -1 + -1x * -1)]
6 + 6x = 4[x + (-3 + 1x)]

Reorder the terms:
6 + 6x = 4[-3 + x + 1x]

Combine like terms: x + 1x = 2x
6 + 6x = 4[-3 + 2x]
6 + 6x = [-3 * 4 + 2x * 4]
6 + 6x = [-12 + 8x]

Solving
6 + 6x = -12 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
6 + 6x + -8x = -12 + 8x + -8x

Combine like terms: 6x + -8x = -2x
6 + -2x = -12 + 8x + -8x

Combine like terms: 8x + -8x = 0
6 + -2x = -12 + 0
6 + -2x = -12

Add '-6' to each side of the equation.
6 + -6 + -2x = -12 + -6

Combine like terms: 6 + -6 = 0
0 + -2x = -12 + -6
-2x = -12 + -6

Combine like terms: -12 + -6 = -18
-2x = -18

Divide each side by '-2'.
x = 9

Simplifying
x = 9